CUDA : error: "transfer of control bypasses initialization of" when creating thrust::device_ptr

I have this code line in my Cuda - C application : #include "cuda_runtime.h" #include "device_launch_parameters.h" #include <thrust/host_vector.h> #include <thrust/device_vector.h> #include <thrust/sort.h> #include <stdio.h> #include <time.h> #include <device_functions.h> int main() { const int size = 32; unsigned int * dev_ips_range_end; unsigned int * ips_range_end = new unsigned int[size]; for (int i = 0; i < size; i++) ips_range_end[i] = i; cudaError_t cudaStatus; cudaStatus = cudaSetDevice(0); if (cudaStatus != cudaSuccess) { fprintf(stderr, "cudaSetDevice failed! Do you have a CUDA-capable GPU installed?"); goto Error; } cudaStatus = cudaMalloc((void**)&dev_ips_range_end, size * sizeof(int)); if (cudaStatus != cudaSuccess) { fprintf(stderr, "Problem !"); goto Error; } // Copy input vectors from host memory to GPU buffers. cudaStatus = cudaMemcpy(dev_ips_range_end, ips_range_end, size * sizeof(unsigned char), cudaMemcpyHostToDevice); if (cudaStatus != cudaSuccess) { fprintf(stderr, "Problem !"); goto Error; } thrust::device_ptr<unsigned int> dev_ips_range_end_ptr(dev_ips_range_end); thrust::inclusive_scan(dev_ips_range_end_ptr, dev_ips_range_end_ptr + size, dev_ips_range_end_ptr); return 0; Error: cudaFree(dev_ips_range_end); } here is the command I used and the output: [Test]$ nvcc -I/usr/local/cuda/include -L/usr/local/cuda/lib kernel.cu -o test.run kernel.cu(27): error: transfer of control bypasses initialization of: variable "dev_ips_range_end_ptr" (42): here kernel.cu(32): error: transfer of control bypasses initialization of: variable "dev_ips_range_end_ptr" (42): here kernel.cu(39): error: transfer of control bypasses initialization of: variable "dev_ips_range_end_ptr" (42): here 3 errors detected in the compilation of "/tmp/tmpxft_000022ad_00000000-9_kernel.cpp1.ii". the same code is working without any problem in visual studio on windows. how to solve this issue ?